Q109 · CSIR-NET Chemistry, December 2011

Paper: CSIR-NET December 2011 · Subject: Physical Chemistry · Chapter: Quantum Chemistry · Topic: Particle In A Box · Marks: 2 · Difficulty: Medium

A particle is constrained in a one dimensional box of length 2 a with potential $\mathrm{V}(\mathrm{x})=\infty ; \mathrm{x}<-\mathrm{a}, \mathrm{x}>\mathrm{a}$ and $\mathrm{V}(\mathrm{x})=0 ;-\mathrm{a} \leq \mathrm{x} \leq \mathrm{a}$. Energy difference between levels $\mathrm{n}=3$ and $\mathrm{n}=2$ is
(a)$\frac{5 \mathrm{h}^{2}}{8 \mathrm{ma}^{2}}$
(b)$\frac{9 \mathrm{h}^{2}}{8 \mathrm{ma}^{2}}$
(c)$\frac{9 \mathrm{h}^{2}}{32 \mathrm{ma}^{2}}$
(d)$\frac{5 \mathrm{h}^{2}}{32 \mathrm{ma}^{2}}$
Answer
Answer: D ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
Box length 2a: E_n = n²h²/(8m(2a)²) = n²h²/(32ma²). E₃ − E₂ = 5h²/(32ma²).

Study loop for Quantum Chemistry

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app