The half life of a zero order reaction (A → P) is given by (k= rate constant) :

(a) t1/2=([A]₀)/2k. Explanation: Zero order: [A] = [A]₀ − kt, so [A]₀/2 = [A]₀ − kt₁/₂ ⇒ t₁/₂ = [A]₀/2k.

Q15 · CSIR-NET Chemistry, December 2011

Paper: CSIR-NET December 2011 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Marks: 2 · Difficulty: Easy

The half life of a zero order reaction $(A \rightarrow P)$ is given by $(k=$ rate constant $)$ :

(a)$t_{1/2}=\dfrac{[A]_{0}}{2k}$

(b)$t_{1/2}=\dfrac{2.303}{k}$

(c)$t_{1/2}=\dfrac{[A]_{0}}{k}$

(d)$t_{1/2}=\dfrac{1}{k[A]_{0}}$

Answer

Answer: A ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation

Zero order: [A] = [A]₀ − kt, so [A]₀/2 = [A]₀ − kt₁/₂ ⇒ t₁/₂ = [A]₀/2k.

Study loop for Chemical Kinetics