Q56 · CSIR-NET Chemistry, December 2011

Paper: CSIR-NET December 2011 · Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Marks: 2 · Difficulty: Medium

The reaction between $\mathrm{NH}_{4} \mathrm{Br}$ and Na metal in liquid ammonia (solvent) results in the products
(a)NaBr, HBr
(b)$\mathrm{NaBr}, \mathrm{H}_{2}$
(c)$\mathrm{H}_{2}, \mathrm{HBr}$
(d)$\mathrm{HBr}, \mathrm{H}_{2}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
NH₄⁺ is the acid of liquid ammonia; sodium reduces it: 2NH₄Br + 2Na → 2NaBr + H₂ + 2NH₃.

Study loop for Main Group Elements

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app