The greater stability of $\left(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}-\mathrm{CH}_{2}{ }^{-}\right)_{4} \mathrm{Ti}(\mathrm{A})$ compared to that of $\left(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CH}_{2}{ }^{-}\right)_{4} \mathrm{Ti}(\mathrm{B})$ is due to
(a)Hyperconjugation present in complex (A)
(b)$\beta$-hydride elimination is not possible in complex (A)
(c)Steric protection of titanium from reactive species in complex (A)
(d)The stronger nature of Ti-C bond in complex (A).
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Neopentyl groups have no β-hydrogen, so the usual β-hydride elimination decomposition path is blocked; isobutyl groups have β-H and decompose readily.