Q81 · CSIR-NET Chemistry, December 2011

Paper: CSIR-NET December 2011 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Hard

The concentration of a reactant undergoing decomposition was $0.1, 0.08$ and $0.067 \mathrm{mol} \mathrm{L}^{-1}$ after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is
(a)0
(b)1
(c)2
(d)3
Answer
Answer: C ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
1/c: 10.0, 12.5, 14.9 L mol⁻¹ at 1, 2, 3 h — equal increments (≈2.5 per hour), so 1/c is linear in t: second order.

Study loop for Chemical Kinetics

1. Practise the PYQsPrevious-year questions, with answers

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