Q4 · CSIR-NET Chemistry, December 2012

Paper: CSIR-NET December 2012 · Subject: Inorganic Chemistry · Chapter: Inorganic Spectroscopy · Topic: Inorganic Spectroscopy – General · Marks: 2 · Difficulty: Medium

The recoil energy of a Mossabauer nuclide of mass 139 amu is 2.5 MeV. The energy emitted by the nucleus in keV is:

(a)12.5

(b)15.0

(c)20.5

(d)25.0

Answer

Answer: D ✓ checked by 4AB · confidence medium

Explanation

E_R = E_γ²/2Mc² → E_γ = √(2 × 139 × 931.5 MeV × 2.5 meV) ≈ 25 keV (d) (recoil energy is in meV).

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