Q45 · CSIR-NET Chemistry, December 2012

Paper: CSIR-NET December 2012 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Marks: 2 · Difficulty: Easy

The number of possible isomers of $\left[\mathrm{Ru}\left(\mathrm{PPh}_{3}\right)_{2}(\mathrm{acac})_{2}\right](\mathrm{acac}=$ acetylacetonate $)$ is:
(a)2
(b)3
(c)4
(d)5
Answer
Answer: B ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
[Ru(PPh₃)₂(acac)₂]: trans-PPh₃ (achiral, 1) and cis-PPh₃ (chiral, Δ and Λ enantiomers, 2) — three isomers in all.

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