Q70 · CSIR-NET Chemistry, December 2012

Paper: CSIR-NET December 2012 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Easy

Which one of the following will NOT undergo oxidative addition by methyl iodide?
(a)$\left[\mathrm{Rh}(\mathrm{CO})_{2} \mathrm{I}_{2}\right]^{-}$
(b)$\left[\operatorname{Ir}\left(\mathrm{PPh}_{3}\right)_{2}(\mathrm{CO}) \mathrm{Cl}\right]$
(c)$[(\eta^{2}\text{-}\mathrm{CpRu}(\mathrm{CO})_{2}]$
(d)$[(\eta^{5}\text{-}\mathrm{Cp}_{2}\mathrm{Ti}(\mathrm{Me})\mathrm{Cl}]$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Oxidative addition needs a low-valent, electron-rich metal with a stable higher oxidation state; Cp₂Ti(Me)Cl is d⁰ Ti(IV) with no electrons to give and no accessible Ti(VI).

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