Q85 · CSIR-NET Chemistry, December 2012
Paper: CSIR-NET December 2012 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Easy
The Daniel cell is
(a)$\operatorname{Pt}_{\mathrm{I}}(\mathrm{s})|\mathrm{Zn}(\mathrm{s})| \mathrm{Zn}^{2+}(\mathrm{aq}) \| \mathrm{Cu}^{2+}(\mathrm{aq})|\mathrm{Cu}(\mathrm{s})| \operatorname{Pt}_{\mathrm{II}}$
(b)$\mathrm{Pt}_{\mathrm{I}}(\mathrm{s})|\mathrm{Zn}(\mathrm{s})| \mathrm{Zn}^{2+}(\mathrm{aq}) \| \mathrm{Ag}^{2+}(\mathrm{aq})|\mathrm{Ag}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
(c)$\operatorname{Pt}_{\mathrm{I}}(\mathrm{s})|\mathrm{Fe}(\mathrm{s})| \mathrm{Fe}^{2+}(\mathrm{aq}) \| \mathrm{Cu}^{2+}(\mathrm{aq})|\mathrm{Cu}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
(d)$\mathrm{Pt}_{\mathrm{I}}(\mathrm{s})\left|\mathrm{H}_{2}(\mathrm{s})\right| \mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \| \mathrm{Cu}^{2+}(\mathrm{aq})|\mathrm{Cu}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
The Daniell cell is Zn | Zn²⁺ || Cu²⁺ | Cu: zinc is oxidised at the anode and copper(II) is reduced at the cathode (E°cell = 1.10 V).
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