The equilibrium constant for an electrochemical reaction, is [ left[EFe³⁺/Fe²⁺o=0.75,mathrmV, ESn⁴⁺/Sn²⁺o=0.15,mathrmV; dfrac2.303RTF=0.06,mathrmV ight]]

(b) 10²⁰. Explanation: E° = 0.75 − 0.15 = 0.60 V, n = 2: log K = 2 × 0.60/0.06 = 20 (b).

Q87 · CSIR-NET Chemistry, December 2012

Paper: CSIR-NET December 2012 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium

The equilibrium constant for an electrochemical reaction, is

[ left[E_{Fe^{3+}/Fe^{2+}}^{o}=0.75,mathrm{V}, E_{Sn^{4+}/Sn^{2+}}^{o}=0.15,mathrm{V}; dfrac{2.303RT}{F}=0.06,mathrm{V} ight] ]

(a)$10^{10}$

(b)$10^{20}$

(c)$10^{30}$

(d)$10^{40}$

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

E° = 0.75 − 0.15 = 0.60 V, n = 2: log K = 2 × 0.60/0.06 = 20 (b).

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