The $\mathrm{C}=\mathrm{O}$ bond length is 120 pm in $\mathrm{CO}_{2}$. The moment of inertia of $\mathrm{CO}_{2}$ would be close to (masses of C and O are $1.9 \times 10^{-27} \mathrm{kg}$ and $2.5 \times 10^{-27} \mathrm{kg}$, respectively)
(a)$1.8 \times 10^{-45} \mathrm{kgm}^{2}$
(b)$3.6 \times 10^{-45} \mathrm{kgm}^{2}$
(c)$5.4 \times 10^{-45} \mathrm{kgm}^{2}$
(d)$7.2 \times 10^{-45} \mathrm{kgm}^{2}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
C sits on the centre of mass, so I = 2 m_O r² = 2 × 2.5×10⁻²⁷ × (1.2×10⁻¹⁰)² = 7.2×10⁻⁴⁷ kg m² — the option printed as 7.2 (the exponent in the options is a misprint).