The heat capacity of 10 mol of an ideal gas at a certain temperature is 300 JK⁻¹ at constant pressure. The heat capacity of the same gas at the same temperature and at constant volume would be

(b) 217 JK⁻¹. Explanation: CV = Cp − nR = 300 − 10 × 8.314 = 217 J K⁻¹.

Q119 · CSIR-NET Chemistry, December 2013

Paper: CSIR-NET December 2013 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Marks: 2 · Difficulty: Medium

The heat capacity of 10 mol of an ideal gas at a certain temperature is $300 \mathrm{JK}^{-1}$ at constant pressure. The heat capacity of the same gas at the same temperature and at constant volume would be

(a)$383 \mathrm{JK}^{-1}$

(b)$217 \mathrm{JK}^{-1}$

(c)$134 \mathrm{JK}^{-1}$

(d)$466 \mathrm{JK}^{-1}$

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

C_V = C_p − nR = 300 − 10 × 8.314 = 217 J K⁻¹.

Study loop for Thermodynamics

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