Q31 · CSIR-NET Chemistry, December 2013
Paper: CSIR-NET December 2013 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Marks: 2 · Difficulty: Easy
According to Arrhenius equation ( $k=$ rate constant and $T=$ temperature)
(a)$\ln k$ decreases linearly with $1/T$
(b)$\ln k$ decreases linearly with $T$
(c)$\ln k$ increases linearly with $1/T$
(d)$\ln k$ increases linearly with $T$
Answer
Answer: A ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
ln k = ln A − Ea/RT: a plot of ln k against 1/T is a straight line of negative slope −Ea/R.
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