For a first order reaction $A \rightarrow$ products, the plot of $\ln\left(\dfrac{[A]_t}{[A]_0}\right)$ vs time, where $[A]_0$ and $[A]_t$ to cocentration at time $=0$ and $t$ respectively, is
(a)a straight line with a positive slope passing through origin
(b)a straight line with a negative slope passing through origin.
(c)an exponential curve asymptotic to the time axis
(d)a curve asymptotic to the $\ln\left(\dfrac{[A]_t}{[A]_0}\right)$ axis.
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
For first order, ln([A]t/[A]₀) = −kt: a straight line of slope −k through the origin (b).