Q37 · CSIR-NET Chemistry, December 2013

Paper: CSIR-NET December 2013 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Partial Molar Quantities · Marks: 2 · Difficulty: Easy

The chemical potential $\left(\mu_{i}\right)$ of the $i^{\text {th }}$ component is defined as
(a)$\mu_{i}=\left(\frac{\partial U}{\partial n_{i}}\right)_{T, P}$
(b)$\mu_{i}=\left(\frac{\partial H}{\partial n_{i}}\right)_{T, P}$
(c)$\mu_{i}=\left(\frac{\partial A}{\partial n_{i}}\right)_{T, P}$
(d)$\mu_{i}=\left(\frac{\partial G}{\partial n_{i}}\right)_{T, P}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
At constant T and P the chemical potential is μ_i = (∂G/∂n_i)_{T,P,n_j}. The derivatives of U, H and A give μ_i only at their own natural variables (S,V), (S,P), (T,V).

Study loop for Thermodynamics

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