Q93 · CSIR-NET Chemistry, December 2013
Paper: CSIR-NET December 2013 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Easy
Electrolysis of an aqueous solution of 1.0 M NaOH results in
(a)Na at the cathode and $\mathrm{O}_{2}$ at the anode.
(b)$\mathrm{H}_{2}$ at the cathode and $\mathrm{O}_{2}$ at the anode.
(c)Na and $\mathrm{H}_{2}$ at the cathode, and $\mathrm{O}_{2}$ at the anode.
(d)$\mathrm{O}_{2}$ at the cathode and $\mathrm{H}_{2}$ at the anode.
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Water is reduced to H₂ at the cathode (Na⁺ cannot be reduced in water) and hydroxide is oxidised to O₂ at the anode.
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