Q48 · CSIR-NET Chemistry, December 2014

Paper: CSIR-NET December 2014 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Reaction Mechanisms Substitution · Marks: 2 · Difficulty: Easy

In the following reaction $\left[\mathrm{PtCl}_{4}\right]^{2-}+\mathrm{NO}_{2}^{-}$, is $\rightarrow \mathrm{A}+\mathrm{NH}_{3} \rightarrow \mathrm{B}$, compound B is
(a)trans- $\left[\mathrm{PtCl}_{2}\left(\mathrm{NO}_{2}\right)\left(\mathrm{NH}_{3}\right)\right]^{-}$
(b)cis- $\left[\mathrm{PtCl}\left(\mathrm{NO}_{2}\right)\left(\mathrm{NH}_{3}\right)\right]^{-}$
(c)trans- $\left[\mathrm{PtCl}_{2}\left(\mathrm{NH}_{3}\right)_{2}\right]$
(d)cis- $\left[\mathrm{PtCl}_{3}\left(\mathrm{NO}_{2}\right)_{2}\right]^{2-}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
NO₂⁻ replaces one Cl⁻ to give [PtCl₃(NO₂)]²⁻; NO₂⁻ has the stronger trans effect, so NH₃ replaces the Cl trans to it — trans-[PtCl₂(NO₂)(NH₃)]⁻ (a).

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