Q69 · CSIR-NET Chemistry, December 2014

Paper: CSIR-NET December 2014 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Medium

Reductive elimination step in hydrogenation of alkenes by Wilkinson catalyst results in (neglecting solvent in coordination sphere of Rh)
(a)T-shaped $\left[\mathrm{Rh}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}\right]$
(b)Trigonal-planar $\left[\mathrm{Rh}\left(\mathrm{PPh}_{3}\right)_{2} \mathrm{Cl}\right]^{2+}$
(c)T-shaped $\left[\mathrm{Rh}(\mathrm{H})\left(\mathrm{PPh}_{3}\right) \mathrm{Cl}\right]^{+}$
(d)Trigonal-planar $\left[\mathrm{Rh}(\mathrm{H})\left(\mathrm{PPh}_{3}\right)_{2}\right]$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
After reductive elimination of the alkane the catalyst returns as the 14-electron T-shaped [RhCl(PPh₃)₂], which re-adds H₂ (solvent completes the coordination sphere).

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