Q47 · CSIR-NET Chemistry, December 2015
Paper: CSIR-NET December 2015 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
The correct statement among the following is
(a)$\mathrm{N}_{2}$ has higher bond order than $\mathrm{N}_{2}^{+}$and hence has larger bond length compared to
(b)has higher bond order than $\mathrm{N}_{2}$ and hence has larger bond length compared to $\mathrm{N}_{2}$
(c)$\mathrm{N}_{2}$ has higher bond order than $\mathrm{N}_{2}^{+}$and hence has higher dissociation energy compared to
(d)$\mathrm{N}_{2}$ has lower bond order than $\mathrm{N}_{2}^{+}$and hence has lower dissociation energy compared to energy
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
N₂ has bond order 3 and N₂⁺ has 2.5. N₂ therefore has the shorter bond and the higher dissociation energy (c).
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