Q49 · CSIR-NET Chemistry, December 2015
Paper: CSIR-NET December 2015 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
The ground state electronic configuration of $\mathrm{C}_{2}$, using all electron is
(a)$\sigma_{\mathrm{1s}}^{2}\sigma_{\mathrm{1s}}^{*2}\sigma_{\mathrm{2s}}^{2}\sigma_{\mathrm{2s}}^{*2}\sigma_{\mathrm{2p}}^{2}\pi_{\mathrm{2p}}^{2}$
(b)$\sigma_{\mathrm{1s}}^{2}\sigma_{\mathrm{1s}}^{*2}\sigma_{\mathrm{2s}}^{2}\sigma_{\mathrm{2s}}^{*2}\sigma_{\mathrm{2p}}^{2}\pi_{\mathrm{2p}}^{*2}$
(c)$\sigma_{\mathrm{1s}}^{2}\sigma_{\mathrm{1s}}^{*2}\sigma_{\mathrm{2s}}^{2}\sigma_{\mathrm{2s}}^{*2}\pi_{\mathrm{2p}}^{2}\sigma_{\mathrm{2p}}^{1}\sigma_{\mathrm{2p}}^{*1}$
(d)$\sigma_{\mathrm{1s}}^{2}\sigma_{\mathrm{1s}}^{*2}\sigma_{\mathrm{2s}}^{2}\sigma_{\mathrm{2s}}^{*2}\pi_{\mathrm{2p}}^{4}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
C₂ has 12 electrons. Because of s–p mixing, π2p lies below σ2p, so the configuration is σ1s² σ*1s² σ2s² σ*2s² π2p⁴ (d).
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