The W-W bond order in [W (η⁵-C₅ H₅)(μ-Cl)(CO)₂]₂ is

Q72 · CSIR-NET Chemistry, December 2015

Paper: CSIR-NET December 2015 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Marks: 2 · Difficulty: Easy

The W-W bond order in $\left[\mathrm{W}\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right)(\mu-\mathrm{Cl})(\mathrm{CO})_{2}\right]_{2}$ is

(a)three

(b)two

(c)one

(d)zero

Answer

Answer: D ✓ checked by 4AB · confidence high

Explanation

Each W: 6 + Cp 5 + 2 CO 4 + its own μ-Cl 1 + the lone pair of the other bridging Cl 2 = 18. No W–W bond is needed: bond order zero.

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