Heating a sample of [ (η⁵-C₅ H₅) Mo(CO)₃]₂ results in the formation of [ (η⁵-C₅ H₅) Mo(CO)₂] with elimination of 2 equivalents of CO. The Mo-Mo bond order in this reaction changes from

(c) 1 to 3. Explanation: Mo–Mo bond order goes from 1 to 3 (c).

Q84 · CSIR-NET Chemistry, December 2015

Paper: CSIR-NET December 2015 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Medium

Heating a sample of $\left[\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Mo}(\mathrm{CO})_{3}\right]_{2}$ results in the formation of $\left[\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Mo}(\mathrm{CO})_{2}\right]$ with elimination of 2 equivalents of CO. The Mo-Mo bond order in this reaction changes from

(a)2 to 3

(b)1 to 2

(c)1 to 3

(d)2 to 4

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

Mo–Mo bond order goes from 1 to 3 (c).

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