Q94 · CSIR-NET Chemistry, December 2015

Paper: CSIR-NET December 2015 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Medium

According to the transition state theory, one of the vibrations in the activated complex is a loose vibration. The partition function for this loose vibration is equal to ( $\mathrm{k}_{\mathrm{B}}$ is the Boltzmann's constant and h is the Planck's constant)

(a)$\mathrm{k}_{\mathrm{B}} \mathrm{T} / \mathrm{h}$

(b)$\mathrm{hv} / \mathrm{k}_{\mathrm{B}} \mathrm{T}$

(c)$\mathrm{k}_{\mathrm{B}} \mathrm{T}$

(d)$\mathrm{k}_{\mathrm{B}} \mathrm{T} / \mathrm{hv}$

Answer

Answer: D ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation

For a vibration with hν ≪ kT the partition function 1/(1 − e^{−hν/kT}) → k_BT/hν; the kT/h factor of TST comes from combining it with ν.

Study loop for Chemical Kinetics

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app