Q111 · CSIR-NET Chemistry, December 2016

Paper: CSIR-NET December 2016 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Marks: 2 · Difficulty: Medium

The equation of state for one mole of a gas is given by $\mathrm{PV}-\mathrm{b}=\mathrm{RT}$, where b and R are constants. The value of $\left(\frac{\partial \mathrm{H}}{\partial \mathrm{P}}\right)_{\mathrm{T}}$ is
(a)$V-b$
(b)b
(c)0
(d)$\mathrm{RT} / \mathrm{P}+\mathrm{b}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
(∂H/∂P)_T = V − T(∂V/∂T)_P = b (b).

Study loop for Thermodynamics

1. Practise the PYQsPrevious-year questions, with answers

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