Q34 · CSIR-NET Chemistry, December 2016

Paper: CSIR-NET December 2016 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Marks: 2 · Difficulty: Medium

The equation of state for one mole of a gas is given by $P(V-b)=RT$, where $b$ and $R$ are constants. The value of $\left(\frac{\partial H}{\partial P}\right)_{T}$ is
(a)$V-b$
(b)$b$
(c)0
(d)$\frac{R T}{P}+b$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
(∂H/∂P)_T = V − T(∂V/∂T)_P; with V = RT/P + b, T(∂V/∂T)_P = RT/P, so the result is b (b).

Study loop for Thermodynamics

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