For $\left[\mathrm{Ce}\left(\mathrm{NO}_{3}\right)_{4}\left(\mathrm{OPPh}_{3}\right)_{2}\right]$ from the followingA. Its aqueous solution yellow-orange inB. Coordination number of Ce is tenC. It shows metal to ligand charge transferD. It is diamagnetic in natureThe correct answer is
(a)A and B
(b)A and C
(c)A, B and D
(d)B, C and D
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
[Ce(NO₃)₄(OPPh₃)₂] contains Ce(IV), which is 4f⁰ and diamagnetic. It is yellow-orange from O→Ce LMCT, not MLCT. Four bidentate nitrates plus two OPPh₃ give CN 10. A, B and D (c).