Q61 · CSIR-NET Chemistry, December 2016
Paper: CSIR-NET December 2016 · Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Marks: 2 · Difficulty: Easy
The final product(s) of the reaction of arachno borane, $\mathrm{B}_{4} \mathrm{H}_{10}$ with $\mathrm{NMe}_{3}$ is/are
(a)$[\mathrm{BH_3.NMe_3}]$ and $[\mathrm{B_3H_7.NMe_3}]$
(b)$\left[\mathrm{BH}_{2}\left(\mathrm{NMe}_{3}\right)_{2}\right]^{+}\left[\mathrm{B}_{3} \mathrm{H}_{8}\right]^{-}$
(c)$\left[\mathrm{B}_{4} \mathrm{H}_{10} . \mathrm{NMe}_{3}\right]$
(d)$\left[\mathrm{B}_{4} \mathrm{H}_{10} . \mathrm{NMe}_{3}\right]$ and $\left[\mathrm{BH}_{2}\left(\mathrm{NMe}_{3}\right)_{2}\right]^{+}\left[\mathrm{B}_{3} \mathrm{H}_{8}\right]^{-}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
NMe₃ cleaves the arachno-B₄H₁₀ unsymmetrically: BH₃·NMe₃ + B₃H₇·NMe₃.
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