Q68 · CSIR-NET Chemistry, December 2016

Paper: CSIR-NET December 2016 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Marks: 2 · Difficulty: Easy

The correct geometry of $\left[\mathrm{Rh}_{6} \mathrm{C}(\mathrm{CO})_{15}\right]^{2-}$ is
(a)octahedron
(b)pentagonal pyramid
(c)trigonal prism
(d)monocapped square pyramid
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
[Rh₆C(CO)₁₅]²⁻ has 90 electrons (14n + 6), one more pair than the closo octahedron, and adopts a trigonal prism with the carbide at its centre.

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