Q95 · CSIR-NET Chemistry, December 2016

Paper: CSIR-NET December 2016 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Molecular Spectroscopy – General · Marks: 2 · Difficulty: Medium

${ }^{1} \mathrm{H} \mathrm{NMR}$ spectrum of an organic compound recorded on a 500 MHz spectrometer showed a quartet with line positions at 1759, 1753, 1747, 1741 Hz. Chemical shift and coupling constant (Hz) of the quartet are
(a)3.5 ppm, 6 Hz
(b)3.5 ppm, 12 Hz
(c)3.6 ppm, 6 Hz
(d)3.6 ppm, 12 Hz
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
Centre (1759 + 1741)/2 = 1750 Hz → 1750/500 = 3.5 ppm; spacing 6 Hz = J.

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