In the following transformation, the mode of electrocyclization A and the major product B areheatB
(a)$A=(4n)e^{-}$, dis;B=
(b)$A=(4n+2)e^{-}$, dis;
(c)$A=(4n)e^{-}$, con;B=
(d)$A=(4n+2)e^{-}$, con;
Answer
Answer: B ✓ checked by 4AB · confidence medium
Explanation
COT → bicyclo[4.2.0]octatriene is a 6π (4n+2), thermal disrotatory closure. OsO₄ then dihydroxylates the cyclobutene from the convex face, on the same side as the ring-fusion H (b).