Q77 · CSIR-NET Chemistry, December 2017

Paper: CSIR-NET December 2017 · Subject: Physical Chemistry · Chapter: Solid State Chemistry · Topic: Crystal Systems Lattices · Marks: 2 · Difficulty: Medium

The separation of the (123) planes of an orthorhombic unit cell is 3.12 nm . The separation of (246) and (369) planes are, respectively,

(a)1.56 nm and 1.04 nm

(b)1.04 nm and 1.56 nm

(c)3.12 m and 1.50nm

(d)1.04 nm and 3.12 nm

Answer

Answer: A ✓ checked by 4AB · confidence high

Explanation

(246) = 2 × (123) ⇒ d = 3.12/2 = 1.56 nm; (369) = 3 × (123) ⇒ d = 3.12/3 = 1.04 nm.

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