(b) TS+Σ μi ni. Explanation: G = Σμᵢnᵢ and H = G + TS, so H = TS + Σμᵢnᵢ (b).

Q82 · CSIR-NET Chemistry, December 2017

Paper: CSIR-NET December 2017 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Laws State Functions · Marks: 2 · Difficulty: Easy

Enthalpy is equal to

(a)$\mathrm{TS}+\mathrm{PV}+\Sigma \mu_{\mathrm{i}} \mathrm{n}_{\mathrm{i}}$

(b)$\mathrm{TS}+\Sigma \mu_{\mathrm{i}} \mathrm{n}_{\mathrm{i}}$

(c)$\sum \mu_{\mathrm{i}} \mathrm{n}_{\mathrm{i}}$

(d)$\mathrm{PV}+\Sigma \mu_{\mathrm{i}} \mathrm{n}_{\mathrm{i}}$

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

G = Σμᵢnᵢ and H = G + TS, so H = TS + Σμᵢnᵢ (b).

Study loop for Thermodynamics