Q59 · CSIR-NET Chemistry, December 2018

Paper: CSIR-NET December 2018 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Raman · Marks: 2 · Difficulty: Medium

The third and fourth lines in the rotational Raman spectrum of CO are separated by $8 \mathrm{cm}^{-1}$. The CO bond length is given by

(a)$\sqrt{\frac{\mathrm{h}}{16 \pi^{2} \mu \mathrm{C}}}$

(b)$\sqrt{\frac{3 \mathrm{h}}{32 \pi^{2} \mu \mathrm{C}}}$

(c)$\sqrt{\frac{\mathrm{h}}{32 \pi^{2} \mu \mathrm{C}}}$

(d)$\sqrt{\frac{5 \mathrm{h}}{32 \pi^{2} \mu \mathrm{C}}}$

Answer

Answer: A ✓ checked by 4AB · confidence high

Explanation

Adjacent rotational Raman lines are 4B apart, so B = 2 cm⁻¹. B = h/(8π²cI) ⇒ I = h/(16π²c), and r = √(I/μ) = √[h/(16π²μc)].

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