Q64 · CSIR-NET Chemistry, December 2018

Paper: CSIR-NET December 2018 · Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Thermodynamics – General · Marks: 2 · Difficulty: Easy

The free energy [A-A(0)] of a system with 10 non interacting spins $(\mathrm{S}=\mathrm{I})$ is

(a)$-\mathrm{k}_{\mathrm{b}} \mathrm{T} \ln (3)$

(b)$-10 \mathrm{k}_{\mathrm{b}} \mathrm{T} \ln (3)$

(c)$-\mathrm{k}_{\mathrm{b}} \mathrm{T} \ln (0.3)$

(d)$-10 \mathrm{k}_{\mathrm{b}} \mathrm{T} \ln (0.3)$

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

A − A(0) = −NkT ln q with q = 3 for each spin-1 particle (m_s = −1, 0, +1): −10 k_BT ln 3.

Study loop for Statistical Thermodynamics