Paper: CSIR-NET December 2019 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium
The cell potential (in V) of a $\mathrm{Ag} / \mathrm{AgCl} / \mathrm{KCl}$ electrode connected to the standard hydrogen electrodeat 298 K is closest to (Given $\mathrm{E}_{\left(\mathrm{AgCl} / \mathrm{Ag} \cdot \mathrm{Cl}^{-}\right)}^{0}=0.222 \mathrm{V}$ and assume that the activity of KCl is 0.01 )
(a)0.197
(b)0.297
(c)0.340
(d)0.440
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
E = E°(AgCl/Ag) − 0.0592 log a(Cl⁻) = 0.222 − 0.0592 log 0.01 = 0.222 + 0.118 = 0.340 V.