Q121 · CSIR-NET Chemistry, December 2019
Paper: CSIR-NET December 2019 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Hard
The concentration $(\mathrm{C})$ of a compound undergoing decomposition as a function of time $(\mathrm{t})$ is given below: | t/min | 0 | 1 | 2 | 4 | 6 |
|---|
| C/M | 1.00 | 0.80 | 0.67 | 0.50 | 0.40 |
The order of the reaction is Options: Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
1/C = 1.00, 1.25, 1.49, 2.00, 2.50 at t = 0, 1, 2, 4, 6 min — linear in t with slope 0.25 M⁻¹ min⁻¹, so the reaction is second order (option 2).
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