Q135 · CSIR-NET Chemistry, December 2019

Paper: CSIR-NET December 2019 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Vibrational · Marks: 2 · Difficulty: Medium

The vibrational transition energies of a diatomic molecule corresponding to $\mathrm{v}=1 \leftarrow \mathrm{v}=0$ and $\mathrm{v}=2 \leftarrow \mathrm{v}=1$ are $2143.1 \mathrm{cm}^{-1}$ and $2116.1 \mathrm{cm}^{-1}$, respectively. The anharmonic constant $\left(\omega_{\mathrm{e}} \chi_{\mathrm{e}}\right)$ of the molecule in $\mathrm{cm}^{-1}$ is
(a)27
(b)13.5
(c)10
(d)54
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Successive vibrational spacings differ by 2ω_eχ_e: 2143.1 − 2116.1 = 27 ⇒ ω_eχ_e = 13.5 cm⁻¹.

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