The number of geometrical isomers of the complex $\left[\mathrm{RhH}(\mathrm{C} \equiv \mathrm{CR})_{2}\left(\mathrm{PMe}_{3}\right)_{3}\right]$
(a)2
(b)3
(c)4
(d)1
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Octahedral MA₃B₂C (A = PMe₃, B = alkynyl, C = H): fac-A₃ (one isomer), mer-A₃ with the two alkynyls trans (one) or cis (one) — three geometrical isomers.