For the complex shown below in non-fluxional state, the expected ${ }^{31} \mathrm{P}\left\{{ }^{1} \mathrm{H}\right\} \mathrm{NMR}$ resonance(s) is/are $\left[{ }^{31} \mathrm{P}=\mathrm{I}=1 / 2\right]$
(a)one singlet
(b)one doublet
(c)two Singlets
(d)two doublets
Answer
Answer: D ✓ checked by 4AB · confidence medium
Explanation
In the static trigonal-bipyramidal Ir complex the two dppe P atoms sit in inequivalent (axial and equatorial) sites. They couple to each other, giving two doublets (d).