Q78 · CSIR-NET Chemistry, December 2019
Paper: CSIR-NET December 2019 · Subject: Inorganic Chemistry · Chapter: Lanthanides and Actinides · Topic: Lanthanides & Actinides – General · Marks: 2 · Difficulty: Easy
The correct match for column A with column B is : | Column A | Column B |
|---|
| (a) f→f transition | (i) $\mathrm{Tb}^{3+}$ |
| (b) ${ }^{5} \mathrm{D}_{0} \rightarrow{ }^{7} \mathrm{F}_{\mathrm{n}}$ emission | (ii) $\mathrm{Lu}^{3+}$ |
| (c) ${ }^{5} \mathrm{D}_{4} \rightarrow{ }^{7} \mathrm{F}_{\mathrm{n}}$ emission | (iii) $\mathrm{Sm}^{3+}$ |
| (d)Overlapping J levels | (iv) $\mathrm{Eu}^{3+}$ |
(a)(a) - (iv), (b) - (i), (c)-(ii), (d) - (iii)
(b)(a) - (ii), (b) - (iv), (c) - (iii), (d) - (i)
(c)(a) - (ii), (b)-(iv), (c)-(i), (d)-(iii)
(d)(a)- (i), (b)- (iii), (c)-(ii), (d) - (iv)
Answer
Answer: C ✓ checked by 4AB · confidence medium
Explanation
Lu³⁺ (f¹⁴) has no f→f transitions. ⁵D₀→⁷F_J emission is from Eu³⁺ and ⁵D₄→⁷F_J from Tb³⁺. Sm³⁺ has overlapping, closely spaced J levels (c).
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