The reaction of $\mathrm{XeF}_{6}$ with a limited amount of quartz gives compound A . Then on reaction with an equivalent amount of $\mathrm{XeO}_{3}$. A gives B. The products A and B are, respectively
(a)$\mathrm{XeOF}_{2}$ and $\mathrm{XeO}_{2} \mathrm{F}_{2}$
(b)$\mathrm{XeOF}_{4}$ and $\mathrm{XeO}_{2} \mathrm{F}_{2}$
(c)$\mathrm{XeOF}_{2}$ and $\mathrm{XeOF}_{4}$
(d)$\mathrm{XeO}_{2} \mathrm{F}_{2}$ and $\mathrm{XeOF}_{4}$