Q10 · CSIR-NET Chemistry, June 2011

Paper: CSIR-NET June 2011 · Subject: Organic Chemistry · Chapter: General Organic Chemistry · Topic: Stereochemistry R S E Z · Marks: 2 · Difficulty: Medium

The two compounds given below are Question structure 1 of 2, ABC26OR0002 and Question structure 2 of 2, ABC26OR0002
(a)Enantiomers
(b)Identical
(c)Diastereomers
(d)Regioisomers.
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Turn the second drawing over, i.e. rotate it 180° about the vertical axis lying in the plane of the paper. The C=O ring moves to the left, and the wedge/hash bonds swap: the angular Me becomes a wedge and the ring-fusion H a hash.
This is exactly the first drawing (the same trans-decalone, Me and H anti at the ring fusion), so the two compounds are identical (b).

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