The half-life of a zero order reaction (A → P) is given by (k= rate constant):

(a) t1 / 2=([A]₀)/2 k. Explanation: For zero order, [A] = [A]₀ − kt, so t½ = [A]₀/2k (a).

Q101 · CSIR-NET Chemistry, June 2011

Paper: CSIR-NET June 2011 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Marks: 2 · Difficulty: Medium

The half-life of a zero order reaction $(\mathrm{A} \rightarrow \mathrm{P})$ is given by ( $\mathrm{k}=$ rate constant ):

(a)$\mathrm{t}_{1 / 2}=\frac{[\mathrm{A}]_{0}}{2 \mathrm{k}}$

(b)$\mathrm{t}_{1 / 2}=\frac{2.303}{\mathrm{k}}$

(c)$\mathrm{t}_{1 / 2}=\frac{\left[\mathrm{A}_{0}\right]}{\mathrm{k}}$

(d)$\mathrm{t}_{1 / 2}=\frac{1}{\mathrm{k}\left[\mathrm{A}_{0}\right]}$

Answer

Answer: A ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation

For zero order, [A] = [A]₀ − kt, so t½ = [A]₀/2k (a).

Study loop for Chemical Kinetics