Q153 · CSIR NET Chemistry, June 2011
Paper: CSIR NET June 2011 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Metal Carbonyls · Marks: 2 · Difficulty: Medium
Identify the order according to increasing stability of the following organometallic $\mathrm{TiMe}_{4}, \mathrm{Ti}\left(\mathrm{CH}_{2} \mathrm{Ph}\right)_{4}$, $\mathrm{Ti}(\mathrm{i}-\mathrm{Pr})_{4}$, and $\mathrm{TiEt}_{4}(\mathrm{Me}=$ methyl, $\mathrm{Ph}=$ phenyl, i-Pr = isopropyl, $\mathrm{Et}=$ ethyl $)$
(a)$\mathrm{Ti}\left(\mathrm{CH}_{2} \mathrm{Ph}\right)_{4}<\mathrm{Ti}(\mathrm{i}-\mathrm{pr})_{4}<\mathrm{TiEt}_{4}<\mathrm{TiMe}_{4}$
(b)$\mathrm{TiEt}_{4}<\mathrm{TiMe}_{4}<\mathrm{Ti}(\mathrm{i}-\mathrm{Pr})_{4}<\mathrm{Ti}\left(\mathrm{CH}_{2} \mathrm{Ph}\right)_{4}$
(c)$\mathrm{Ti}(\mathrm{i}-\mathrm{Pr})_{4}<\mathrm{TiEt}_{4}<\mathrm{TiMe}_{4}<\mathrm{Ti}\left(\mathrm{CH}_{2} \mathrm{Ph}\right)_{4}$
(d)$\mathrm{TiMe}_{4}<\mathrm{TiEt}_{4}<\mathrm{Ti}(\mathrm{i}-\mathrm{Pr})_{4}<\mathrm{Ti}\left(\mathrm{CH}_{2} \mathrm{Ph}\right)_{4}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
Ti(i-Pr)₄ < TiEt₄ < TiMe₄ < Ti(CH₂Ph)₄ (c).
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