Q39 · CSIR-NET Chemistry, June 2011
Paper: CSIR-NET June 2011 · Subject: Physical Chemistry · Chapter: Gaseous State · Topic: Real Gases Virial · Marks: 2 · Difficulty: Medium
The virial expansion for a real gas can be written in either of the following forms: \[ \begin{array}{l} \dfrac{P\bar{V}}{RT}=1+B_P P+C_P P^{2}+\cdots \\ =1+B_V V+C_V V^{2}+\cdots \end{array} \]
If $B_V=\alpha B_P$ the value of $\alpha$ would be (a)PV/RT
(b)RT/PV
(c)PV
(d)RT
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Equating Z = 1 + B_P·P + … with Z = 1 + B_V/V + … and using P ≈ RT/V to first order gives B_V = RT·B_P, so α = RT.
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