Paper: CSIR-NET June 2011 · Subject: Physical Chemistry · Chapter: Quantum Chemistry · Topic: Quantum Chemistry – General · Marks: 2 · Difficulty: Medium
For a certain particle encountering a barrier, the tunneling probability is approximately $e^{-10}$. If the mass is halved and width of the barrier (rectangular) doubled, approximate value of the tunneling probability will be
(a)$e^{-10/\sqrt{2}}$
(b)$e^{-10 \sqrt{2}}$
(c)$e^{-20 \sqrt{2}}$
(d)$e^{-10}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
T ≈ e^(−2κL), κ ∝ √m. Halving m divides κ by √2; doubling L doubles it: exponent 10 × 2/√2 = 10√2 — T ≈ e^(−10√2) (b).