Under review — part of this question (a structure or an option) is not clear in the source scan. 4AB is checking it against the original book; the answer shown may change.
the amount of energy (in kJ/mol) released during this process is (given: $U=235.0439$ amu, $Ba=141.9164$ amu, $^{91}Kr=90.9234$ amu, neutron $=1.00866$ amu)
(a)$3.12 \times 10^{12}$
(b)$2.8 \times 10^{11}$
(c)$1.0 \times 10^{9}$
(d)$1.68 \times 10^{10}$
Answer
Under review — not yet confirmed.
Answer: D
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
Δm = 236.0522 − (141.9164 + 90.9234 + 3 × 1.00866) = 0.1864 u, i.e. 173.6 MeV = 2.78 × 10⁻¹¹ J per atom. Per mole that is 1.68 × 10¹³ J = 1.68 × 10¹⁰ kJ (d).