Q62 · CSIR-NET Chemistry, June 2011

Paper: CSIR-NET June 2011 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Medium

Match list I (compounds) with list II (structures), and select the correct answer using the codes given below.
List - IList- II
(a) $\mathrm{XeO_4}$(I) Square planar
(b) $\mathrm{BrF_4^{-}}$(ii) Tetrahedral
(c) $\mathrm{SeCl_4}$(iii) Distorted tetrahedral
(a)(A-ii) (B-iii) (C-i)
(b)(A-iii) (B-i) (C-ii)
(c)(A-ii) (B-i) (C-iii)
(d)(A-i) (B-ii) (C-iii)
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
XeO₄ is tetrahedral, BrF₄⁻ square planar (2 lone pairs) and SeCl₄ see-saw, i.e. distorted tetrahedral (c).

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