Q21 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Thermodynamics – General · Marks: 2 · Difficulty: Medium

The correct entropy for 6 identical particles with their occupation number $0,1,2,3$ in four steps is :

(a)$k_{A} \ln 8$

(b)$k_{A} \ln 12$

(c)$k_{B} \ln 60$

(d)$k_{B} \ln 720$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

W = 6!/(0!1!2!3!) = 60, so S = k_B ln 60 (c).

Study loop for Statistical Thermodynamics

1. Practise the PYQsPrevious-year questions, with answers

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