Q24 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium

In the following reactions carried out in liquid $\mathrm{NH}_{3}$
\[ \begin{array}{l} \mathrm{Zn}\left(\mathrm{NH}_{2}\right)_{2}+2 \mathrm{KNH}_{2} \rightarrow \mathrm{K}_{2}\left[\mathrm{Zn}\left(\mathrm{NH}_{2}\right)_{4}\right] \\ \mathrm{K}_{2}\left[\mathrm{Zn}\left(\mathrm{NH}_{2}\right)_{4}\right]+2 \mathrm{NH}_{4} \mathrm{NO}_{3} \rightarrow \mathrm{Zn}\left(\mathrm{NH}_{2}\right)_{2}+2 \mathrm{KNO}_{3}+4 \mathrm{NH}_{3} \end{array} \]
$\mathrm{KNH}_{2}$ and $\mathrm{NH}_{4} \mathrm{NO}_{3}$ act respectively as
(a)Solvo-acid and solvo-base
(b)Solvo-base and solvo-acid
(c)Conjugate acid and conjugate base
(d)Conjugate base and conjugate acid
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
In liquid ammonia NH₂⁻ is the solvent anion (solvo-base) and NH₄⁺ the solvent cation (solvo-acid): KNH₂ dissolves the amide as an amido complex and NH₄NO₃ neutralises it back.

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